find total resistance.if r1=3ohm,r=6ohm,r3=9ohm
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Given,
R₁ = 3 Ω
R₂ = 6 Ω
R₁ and R₂ are in series,
Effective Resistance R = (R₁+R₂)
= (3+6) Ω
= 9 Ω
R and R₃ are in parallel,
Effective Resistance = 1/R = 1/9+1/9
= 1/R = (1+1)/9
= 1/R = 2/9
= R = 9/2 Ω
= R = 4.5 Ω
The Total/Effective Resistance is 4.5 Ω.
I hope this helps.
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