Question

Find total surface area of a cylindrical rod whose height is 6m and radius is 1m.​

Answer 1

Given:

• Height of the cylindrical rod = 6m

• Radius of the cylindrical rod = 1m .

To find :

• Total surface area of cylindrical rod =?

Solution :

• As we know that :

$\star \boxed{ \red{\bold{ t \: s \: a \: of \: cylinder = 2 \: \pi \: r \: (r + h)}}}$

put the given values :

$\implies \bold{ tsa \: of \: cylinder }= \: 2( \frac{22}{7} )(1)(1 + 6) \\ \\ \implies \bold{tsa \: of \: cylinder} = \frac{44}{ \cancel{7}} ( \cancel{7}) \\ \\ \implies \bold{ tsa \: of \: cylinder} = 44 \: {m}^{2}$

•Hence, The total surface area of cylindrical rod is 44m².

Answer 2

$\large\underline\bold{ANSWER \red{\huge{\checkmark}}}$

$\large\underline\bold{GIVEN,}$

$\dashrightarrow Hieght\:of\:cylinder= 6m$

$\dashrightarrow Radius\:of\:cylinder=1m$

$\large\underline\bold{TO\:FIND,}$

$\dashrightarrow Total\:surface\:area\:of\:cylinder.$

✯FORMULA IN USE,

$\large{\boxed{\bf{ \star\:\:Total\:surface\:area\:of\:cylinder= 2\pi r(r+h) \:\: \star}}}$

$\large\underline\bold{SOLUTION,}$

$\dashrightarrow Total\:area\:of\:cylinder= 2\pi r (r+h)$

$\implies 2\times \dfrac{22}{7} \times 1 (1+6)$

$\implies 2\times \dfrac{22}{7}\times 7$

$\implies 2\times \dfrac{22}{\cancel{7}}\times \cancel{7}$

$\implies 2\times 22$

$\implies 44m^2$

$\large{\boxed{\bf{ \star\:\: T.S.A\:of\:cylinder= 44m^2\:\: \star}}}$

$\large\underline\bold{TOTAL\:SURFACE\:AREA\:OF\:CYLINDER= 44m^2}$

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