find. two complementary angels differ by 16. find the angles
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Answered by
10
x+x+16=90
2x+16=90
2x=74
x=37 degrees
x+16=53 degrees
2x+16=90
2x=74
x=37 degrees
x+16=53 degrees
akash197:
please. type next answer
Answered by
11
HI
DON'T WORRY ABOUT IT
THE EXPERT IS HERE
X+X+16=90
2X+16=90
2X=90-16
2X=74
X=74/2
X=37 degree's
@!#@!#@!#@!#@!#@!#@!#
PLEASE PLEASE PLEASE PLEASE MARK AS BRAINLIST ANSWER .
DON'T WORRY ABOUT IT
THE EXPERT IS HERE
X+X+16=90
2X+16=90
2X=90-16
2X=74
X=74/2
X=37 degree's
@!#@!#@!#@!#@!#@!#@!#
PLEASE PLEASE PLEASE PLEASE MARK AS BRAINLIST ANSWER .
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