Math, asked by adalvaralakshmi, 3 months ago

Find two composite numbers between 50 & 90 such that one of the number is a square number and the difference between the numbers is which multiple of 9?​

Answers

Answered by Anonymous
1

Answer:

Answer

i) Number of two-digit number =90−9=81, Total number =90

Probability of being a two-digit number =

90

81

ii) Since there are 9 perfect square numbers such that 1,4,9,16,25,36,49,64,81

Probability of being a perfect square =

90

9

=

10

1

iii) Since there are 12 numbers divisible of 7 such that 7,14,21,28,35,42,49,56,63,70,77,84

Probability of being a perfect square =

90

12

=

15

2

.

Answered by sunnykrpatel54021
2

Step-by-step explanation:

i) Number of two-digit number =90−9=81, Total number =90

Probability of being a two-digit number =

90

81

ii) Since there are 9 perfect square numbers such that 1,4,9,16,25,36,49,64,81

Probability of being a perfect square =

90

9

=

10

1

iii) Since there are 12 numbers divisible of 7 such that 7,14,21,28,35,42,49,56,63,70,77,84

Probability of being a perfect square =

90

12

=

15

2

.

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