Question

find two consecutive even integers such that 2 fifth of the small number exceds 2 eleventh of the larger number by 4​

Answer 1

Let the numbers be x and x+2

$(2 \div 5) \times x ={( 2 \div 11) \times (x + 2)} + 4$

2x/5=(2x+4/11)+4

2x/5-2x/11=4/11+44/11

22x/55-10x/55=48/11

12x=48×5

x=240/12

x=20

x+2=22

Therefore, the numbers are 20 and 22.

Answer 2

Answer:12&14

Step-by-step explanation:

Let the no.s be x and x+2

2/5x=2/11(x+2)+4

2/5x=2/11x+4/11+4

2/5x=2/11x+48/11

2/5x-2/11x=48/11

20/55x=48/11

x=48/11×55/20

x=12

x+2 =14