find two consecutive even integers such that two-fifth of the smaller exceeds two-eleventh of the larger by 4
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Answer:20 & 22
Step-by-step explanation:
1. Let the unknown values be 'x'and 'x+2' since they are consecutive and even
2. 2/5x-2/11(x+2) gives 4 according to the question
3. Solve to get x
4. Then solve for x+2
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