Question

find two consecutive even number such that the smaller of the two is 4 by 5 than the bigger number​

Answer 1

Answer:

Let the numbers be a , a + 2.

given that,

the smaller number is 4/5 than the bigger number.

a = 4/5(a + 2)

a = (4a + 8)/5

5a = 4a + 8

5a - 4a = 8

a = 8

Smaller number = 8

Bigger number = 8 + 2 = 10.

Answer 2

Answer:

this is answer

Step-by-step explanation:

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