Question

Find two consecutive integers such that two fifth of the smaller exceeds two-night of the greater by 4. The integers should be odd

Answer 1

Heya Mate !!!

Your Answer is ; 25 and 27.

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Step by Step Explanation ;-
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=> Let the two consecutive numbers be ;- x and x+2

According to the question ;

=> 2x/5 = 2/9( x+2) + 4

=> 2x/5 = 2x/9 + 4/9 + 4

=> 2x/5 - 2x/9 = 40/9

=> (18x - 10x)/45 = 40/9

=> 8x = 200

=> x = 200/8 = 25

Therefore the two consecutive positive odd no.s are 25 and 27.

Answer 2

Solutions :-


Let the two consecutive integers be x and x + 2 respectively.


According to the question :-

=> 2/5 of x = 2/9 of (x + 2) + 4
=> 2x/5 = (2x + 4)/9 + 4
=> 2x/5 = (2x + 4 + 36)/9
=> 2x/5 = (2x + 40)/9
=> 2x × 9 = 5(2x + 40)
=> 18x = 10x + 200
=> 18x - 10x = 200
=> 8x = 200
=> x = 200/8 = 25


Hence,
First consecutive integers = x = 25
Second consecutive integers = x + 2 = 25 + 2 = 27

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✯ @shivamsinghamrajput ✯