find two consecutive multiple of 3 whose sum is 415
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let the consecutive multiples of 3 be x and x+3
respectively.
then,
x+(x+3)=415
2x+3=415
2x=415-3
2x=412
x=412/2
=206
so, the numbers are 206 and 209 respectively.
HOPE IT HELPS!
respectively.
then,
x+(x+3)=415
2x+3=415
2x=415-3
2x=412
x=412/2
=206
so, the numbers are 206 and 209 respectively.
HOPE IT HELPS!
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