Question

Find two consecutive multiples of 4
whose sum is 180​

Answer 1

Answer:

Let the numbers be =x, x+4

According to the question

180= 2x+4

180-4= 2x

176= 2x

$\frac{176}{2}$=x

88=x

So, numbers are -

$\rightarrow$x=88

$\rightarrow$x= 92

Answer 2

$★ \: {\underline{\purple{\bold{Given \: that \: - \: }}}}$

$\sf \: The \: sum \: of \: two \: consecutive \: multiples \: of \: 4 \: is \: \bold{180}.$

$★ \: {\underline{\purple{\bold{We \: have \: to \: find \: - \: }}}}$

$\sf \: Those \: two \: consecutive \: multiples \: of \: 4.$

Let, the numbers be

• $\sf \bold{k}$
• $\sf \bold{k + 4}$

_______________________

$★ \: \underline{\underline{\purple{\bold{According \: to \: question \: - \: }}}}$

$\sf\implies \: k \: + (k + 4) = 180 \\ \\ \sf\implies \: k + k + 4 = 180 \\ \\ \sf\implies \: 2k + 4 = 180 \\ \\ \sf\implies \: 2k = 180 - 4 \\ \\ \sf\implies \: 2k = 176 \\ \\ \sf\implies \: k = \frac{176}{2} \\ \\ \sf\implies \: k \: = \boxed{\bold\purple{88}}\bigstar$

Now,

• $\sf \: k = \bold\purple{88}$
• $\sf \: k + 4 = \bold\purple{92}$

$\sf\therefore\underline{Hence \: the \: numbers \: are \: \bold{88} \: and \: \bold{92} \: respectively.}$