Find two consecutive multiplies by 3. Whose sum is 415?
Answers
Answered by
0
Step-by-step explanation:
given two consecutive multiples of 3.
3x,3x+3.
given sum is 415.
3x+3x+3=415
6x+3=415
6x=412
x=412/6
Answered by
2
Answer:
First number = 206
second number = 209
Step-by-step explanation:
Let the first number = x
Let the second number = x + 3
According to the question ,
sum of two consecutive multiples by 3 = 415
x + x + 3 = 415
2x + 3 = 415
2x = 415 - 3
2x = 412
x = 412 / 2
x = 206
∴ First consecutive number = x
= 206
Second consecutive number = x + 3
= 206 + 3
= 209.
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