Question

Find two consecutive natural number whose sum is 41​

Answer 1

Answer:

20 and 21

Step-by-step explanation:

20 and 21 are two consecutive numbers whose sum is 41

Answer 2

Let 'x' be one number and 'x+1' be the other number.

Then,

${x}^{2} + {(x + 1)}^{2} = 41$

${x}^{2} + {x}^{2} + 2x + 1 = 41$

${2x}^{2} + 2x - 40 = 0$

${x}^{2} + x - 40 = 0$

As you can see, this is not a perfect square equation. So, the solutions will not be whole numbers.

Plz recheck the question..

Hope it help you...☺