Question

Find two consecutive natural numbers whose sum is 41

Answer 1

Let the First no: be 'n'.
and the Second no: (a consecutive to 'n') be 'n+1'

According to the question.

n+(n+1)=41
→2n+1=41
→2n=40
→n=40/2
→n=20

So,n+1=21

Hence,The Two comsecutive Natural Numbers Whose Sum is 41 are 20 and 21

Answer 2

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The trick here is to find a shortcut so that you don't have to try so many combinations.

 

If you call the first number "n" and you know that the numbers are consecutive, you know that the next number will be "n + 1."

 

And you also know that the two numbers added together will equal 41. So...

 

n + "n + 1" = 41, or 2n + 1 = 41.

 

Take away one from each side, and you get 2n = 40.

 

And if 2 n's are 40, n by itself must be....

 

and n + 1 will be ....