find two consecutive natural numbers whose sum is 63
Answers
Answered by
5
Let the two numbers be x and x+1.
Given, x+(x+1) = 63
2x + 1 = 63
2x = 62
x = 31.
The other number will be x + 1 = 32.
The two numbers are 31 and 32.
Given, x+(x+1) = 63
2x + 1 = 63
2x = 62
x = 31.
The other number will be x + 1 = 32.
The two numbers are 31 and 32.
Answered by
4
Let the two numbers be x and x+1
x+(x+1) = 63
2x+1 = 63
2x = 63-1
2x = 62
x = 62/2
x = 31
x+1 = 31+1 = 32
Therefore the two numbers are 31 and 32
x+(x+1) = 63
2x+1 = 63
2x = 63-1
2x = 62
x = 62/2
x = 31
x+1 = 31+1 = 32
Therefore the two numbers are 31 and 32
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