Question

Find two consecutive numbers such that when the smaller number is subtracted from three times the bigger number, the result is 56 . ​

Answer 1

$\Large\fbox{\color{purple}{ SOLUTION }}$

Let x & (x+2) be the consecutive odd numbers.

Hence,

☞ According to the question, we can write __

3(x+2) -x = 56

⟹ 2x =56 -6

⟹ 2x = 50

⟹ x =25

Therefore,

The two numbers are 25 & (25+2) / 27.

Verification :-

3 ( x+2) -x =56

⟹ 3 (25 +2) -25 = 56

⟹ 56 =56

(verified)

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Answer 2

Answer:

Step-by-step explanation:

let the 1st number be x then 2nd odd number is x+2

3(x+2)-x=56

3x-x+6=56

2x=50

x=25

x+2=27