find two consecutive numbers whose sum is 47
Answers
Answered by
1
Answer:
Let one no. be x
Other no. x+1
so
x+x+1=47
2x+1=47
2x=47-1
x=46/2
x=23
Answered by
0
Let us call our integers:n
and
n+1
our condition is such that:
n+(n+1)=47
solve for
n :2n=47−1
n=46(2) =23
so that our integers will be:
23
and
24
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