Find two consecutive numbers whose sum is 63
Answers
Answered by
4
Let the first number be #x#. Then the next number is #x+1#
So,
#rarr(x)+(x+1)=63#
#rarrx+x+1=63#
#rarr2x+1=63#
#rarr2x=63-1#
#rarr2x=62#
#rarrx=62/2#
#color(green)(rArrx=31#
One number is #31#, so the other number is#color(green)(x+1=32#
Hope this helps! :)
So,
#rarr(x)+(x+1)=63#
#rarrx+x+1=63#
#rarr2x+1=63#
#rarr2x=63-1#
#rarr2x=62#
#rarrx=62/2#
#color(green)(rArrx=31#
One number is #31#, so the other number is#color(green)(x+1=32#
Hope this helps! :)
Answered by
4
hello friend,
Divide 63 by 2;
you get 31.5.
This is non-whole, so take the whole part which is 31.
hope it helps u
Divide 63 by 2;
you get 31.5.
This is non-whole, so take the whole part which is 31.
hope it helps u
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