Question

Find two consecutive odd integer,sum of whose square is 290

Answer 1

Answer:

Step-by-step explanation:

Let the numbers be x and x+2

according to the question..

(x)^2 + (x+2)^2 = 290

x^2 + x^2 + 4 + 2(2)(x) =290

2x^2 + 4 -290 +4x=0

2x^2 +4x -286 =0

2(x^2 + 2x +143)=0

x^2 +13x -11x +143=0

x(x+13) - 11(x +13) =0

(x-11)(x+13)=0

x=11 x=-13

therefore, the numbers are 11 and 13

hope this helps!

Answer 2

Answer:

I hope upper attachment will help you✌