Find two consecutive odd integer,sum of whose square is 290
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Answered by
3
Answer:
Step-by-step explanation:
Let the numbers be x and x+2
according to the question..
(x)^2 + (x+2)^2 = 290
x^2 + x^2 + 4 + 2(2)(x) =290
2x^2 + 4 -290 +4x=0
2x^2 +4x -286 =0
2(x^2 + 2x +143)=0
x^2 +13x -11x +143=0
x(x+13) - 11(x +13) =0
(x-11)(x+13)=0
x=11 x=-13
therefore, the numbers are 11 and 13
hope this helps!
8080638010aniket:
Thnx
Answered by
9
Answer:
I hope upper attachment will help you✌
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