Question

Find two consecutive odd integer sum of whose square is 650

Answer 1

Answer:

17  &  19

or

-17 & -19

Step-by-step explanation:

let say numbers are 2n+1 & 2n+3

(2n+1)^2 + (2n+3)^2 = 650

4n^2 + 1 + 4n + 4n^2 + 9 + 12n = 650

8n^2 + 16n - 640 = 0

n^2 + 2n - 80 = 0

n^2 + 10n - 8n - 80 = 0

(n+10)(n-8)= 0

n = -10  & 8

numbers are 2n+1 & 2n+3

-19 & -17

or

17 & 19