Question

Find two consecutive odd integers such that 4 times the larger is 29 more than 3 times the smaller

Answer 1

Answer:

consecutive integers are 21,23

Step-by-step explanation:

lets call our 2 integers x and x+2

4(x+2)=3x+29 distribute the left side

4x+8=3x+29 subtract 3x and 8 from both sides

x=21

so our consecutive integers are 21,23

Answer 2

SOLUTION

TO DETERMINE

Two consecutive odd integers such that 4 times the larger is 29 more than 3 times the smaller

EVALUATION

Let two consecutive odd integers are x and x + 2

By the given condition

$\displaystyle \sf{ \implies 4(x + 2) = 3x + 29}$

$\displaystyle \sf{ \implies 4x + 8 = 3x + 29}$

$\displaystyle \sf{ \implies 4x - 3x = 29 - 8}$

$\displaystyle \sf{ \implies x = 21}$

Hence the required integers are 21 and 23

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