find two consecutive odd natural numbers sum of whose squares is 970
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Answer:21
Step-by-step explanation:-
1. let the first odd number be x. therefore second one would be x+2.
2. sum of squares of both numbers=970.
3. x^2 +(x+2)^2=970
4.x^2 +x^2 +4x +4=970
5. 2x^2 + 4x - 966=0
6. divide the whole equation by 2.
7. x^2 + 2x -483=0
8. x^2 +23x-21x -483=0
9. x(x+23)-21 (x+ 23)=0
10. ×=21, -23
11. as x is odd number, ans is 21.
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