Question

Find two consecutive odd natural numbers, the sum of whose square is 394. ​

Answer 1

Consider one number be (2n−1), then the next consecutive odd number will be (2n+1)

⇒(2n−1)

2

+(2n+1)

2

=394

⇒4n

2

+1−4n+4n

2

+1+4n=394

⇒8n

2

+2=394

⇒8n

2

=392

⇒n

2

=49

⇒n=7

Therefore, the two consecutive numbers are

(2n−1)=14−1=13

(2n+1)=14+1=15

Hence, the two consecutive numbers are 13 and 15

Step-by-step explanation:

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