find two consecutive odd natural numbers the sum of whose square is 202
Answers
Answered by
5
Let the two consecutive odd numbers be x and x+2 .
It is given that the sum of their squares is equal to 202. Therefore we have x^2 + (x+2)^2 = 202
=> x^2 + x^2 + 4x + 4 = 202
=> 2x^2 + 4x + 4 = 202
subtract 202 from both the sides
=> 2x^2 + 4x - 198 =0
divide all terms by 2
=> x^2 + 2x - 99 =...
Similar questions