Question

Find two consecutive odd numbers such that one-fifth of the smaller exceeds one-ninth of the greater by 2.​

Answer 1

Answer:

Let x and y the two odd numbers,

We are told they are consecutive.

So, y = x + 2

We are also given that

x/3 = y/7 + 6

x = 3(y/7 + 6) = (3y + 126)/7

7x = 3 y 126

7x = 3x + 132 from the first equation

4x = 132

x = 33 and y = 35

One third of x is 11 and one seventh of 35 is 5 and their difference is 6.

Answer 2

Answer:

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