Math, asked by gurumurthyhc974, 6 months ago

Find two consecutive odd numbers such that one-seventh of the greater number may
fall short of one fifth of the lesser number by 4.​

Answers

Answered by arjun4671
4

Answer:

-3/2&-1/2

Step-by-step explanation:

1/7(x)=1/5(x-1)÷4

1/7(x)=x-1/20

20x=7x-7

x= -7/14

x=-1/2

there fore -3/2&-1/2

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Answered by santoshh2006gmailcom
4

Step-by-step explanation:

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