Find two consecutive odd numbers such that one-seventh of the greater number may
fall short of one fifth of the lesser number by 4.
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Answer:
-3/2&-1/2
Step-by-step explanation:
1/7(x)=1/5(x-1)÷4
1/7(x)=x-1/20
20x=7x-7
x= -7/14
x=-1/2
there fore -3/2&-1/2
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