Question

find two consecutive positive even number whose square have the sum is 452​

Answer 1

Solution:

Let x , (x+2) are two consecutive even positive numbers.

According to the problem given,

x²+ (x+2)² = 452

=> x²+x²+4x+4-452 = 0

=> 2x²+4x-448 = 0

On dividing each term by 2, we

get,

=> x²+2x-224=0

Splitting the middle term, we get

=> x² +16x-14x-224 = 0

=> x(x+16) -14(x+16)=0

=> (x+16)(x-14)=0

=>x+16 = 0 or x-14 = 0

=>x = 14

/* x is positive even number */

Now ,

Required two positive even consecutive numbers are,

x = 14 ,

x+2 = 14+2 = 16

••••

Answer 2

Answer:

Step-by-step explanation: