Find two consecutive positive even numbers the sum of whose squares is 340
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let 1st positive integer=x
2nd. =x+2
,.
x²+(x+2)²=340
2x²+4x-336=0
x²+2x-168=0
x²+14x-12x-168=0
x(x+14)-12(x+14)=0
x=12 or-14
x=-14 is not possible as for positive even no
therefore
x=12
first positive even no =12
2nd positive even no=12+2
=14
2nd. =x+2
,.
x²+(x+2)²=340
2x²+4x-336=0
x²+2x-168=0
x²+14x-12x-168=0
x(x+14)-12(x+14)=0
x=12 or-14
x=-14 is not possible as for positive even no
therefore
x=12
first positive even no =12
2nd positive even no=12+2
=14
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