Math, asked by manojkpwild, 1 month ago

Find two consecutive positive integers such that the square of the first decreased

by 17 equals 4 times the second​

Answers

Answered by BrainliestBrainAT
0

Answer:

let the two numbers be x+1 and x

(x+1)^2-17=4(x)^2

x^2 +2x+1-17=4x^2

3x^2-2x+16=0

is the question wrong? equation is giving complex roots. But get the idea

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