Question

Find two consecutive positive integers, sum of whose squares is 365. please explain properly I can't properly ​

Answer 1

Step-by-step explanation:

let the no. be  x and x+1

  then we have x²+(x+1)²=365

                     2x²+2x-364=0

                     x²+x-182=0

                     x²+14x-13x-182=0

                     (x+14)(x-13)=0

                 That gives x=13 Avoiding negative value

                 one number is 13 and other one 14.