Question

Find two consecutive positive integers sum of whose squares is 365. ​

Answer 1

After getting

${x}^{2} + x - 182 = 0$

do the factorisation method..

${x}^{2} + 14x - 13x - 182 = 0 \\ x(x + 14) - 13(x + 14) \\( x + 14)(x - 13)$

therefore x=13

:. First no=13

:. second no= x+1

=13+1

=14

Answer 2

Answer:

$13 \: and \: 14$

Step-by-step explanation:

It is the correct answer.

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