Question

Find two consecutive positive integers, sum of whose squares is 365.

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Answer 1

Step-by-step explanation:

numbers are consecutive, let first number be x thus, second no is x + 2

because consecutive number have difference of 2 between them

thus, (x) square + (x +2) square = 365

(x + x + 2) square = 365

(2x) square + 2 square = 365

4x square + 4 = 365

4x square = 365 - 4

x square = 361/4

x = root 361/4

x = 19/2

thus x= 9.5 and 2+x = 11.5

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Answer 2

Answer:

$13 \: and \: 14$

Step-by-step explanation:

It is the correct answer.

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