Question

Find two consecutive positive integers sum of whose squares is 925 by
quadratic formula

Answer 1

let first integer be x
then its consecutive integer be (x+1)

according to question

x^2 + (x+1)^2 = 925

2x^2 + 2x - 924 = 0

x^2 + x - 462 = 0

x = -1 +- √1 + 4*462 / 2

x = -1 +- 43/2

x = -1 + 43 /2 = 21

x = -1 - 43/2 = -22

x = 21 , -22

hope it helped you....

Answer 2

Answer:

What will be the nature of roots of quadratic equation 5x2-9x+14=0.