find two consecutive positive integers whose sum of squares is 365
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the two positive integers are 13 and 14 as square of 13 and 14 are 169 and 196 so 169+196=365
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Let us say, the two consecutive positive integers be x and x + 1.
Therefore, as per the given statement,
Thus, either, x + 14 = 0 or x – 13 = 0, [/tex]
since, the integers are positive, so x can be 13, only.
So, x + 1 = 13 + 1 = 14
Therefore, the two consecutive positive integers will be 13 and 14
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