Question

Find two consecutive positive odd integers whose productis 483

Answer 1

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հίί ʍαtε_______✯◡✯
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һєяє' ʏȏȗя ѧṅśwєя ʟȏȏҡıṅɢ ғȏя________
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✯ x(x+2)=483

☛x2+2x-483=0

☛x2+(23-21)x-483=0

☛x2+23x-21x-483=0

☛x(x+23)-21(x+23)=0

☛(x-21)(x+23)=0

☛x=21; x=-23; Rejecting the negative value,

☛x=21

☛First number= 21

☛Second Number= 23

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$hope \: it \: helps$


★BRAINLY★

Answer 2

let the two consecutive positive odd integers be x and x+2.

Then,
x(x+2)=483
x^2+2x=483
x^2+2x-483=0
x^2+23x-21x-483=0
x(x+23)-21(x+23)=0

Therefore, x=21 and 23