Question

find two consecutive positive odd integers whose sum is 76
rs Aggarwal ​

Answer 1

Answer:

37 and 39

Step-by-step explanation:

Let the numbers be (2x - 1) and (2x + 1).

(2x - 1) + (2x + 1) = 76

2x + 2x + 1 - 1 = 76

4x = 76

x = 19

Thus,

1st number = (2 × 19) - 1 = 38 - 1 = 37

2nd number = (2 × 19) + 1 = 38 + 1 = 39

Answer 2

$\small\underline \purple{Given -:}$

→That the sum of 2 consecutive positive odd numbers is 76.

$\small \underline \purple{To \: Find -:}$

→The consecutive positive odd integers , let the 1 consecutive number be x .

and second = x +2

$\small \underline \purple{ATQ \: ,}$

$\red{⟶x + (x + 2) = 76}$

$\red{⟶x + x + 2 = 76}$

$\red{⟶2x + 2 = 76}$

$\red {⟶2x = 76 - 2}$

$\red {⟶2x = 74}$

$\red{⟶x = \frac{74}{2} = 37}$

Hence , the first integer is 37 .

And the second one is 37+2 = 39 !