Question

Find two consicutive odd integers such that two fifth of the smaller exeed two ninth of greater the by 4

Answer 1

let the odd integers be x , x+2
according to question
(2/5)*x-(2/9)*(x+2)= 4
2x/5- 2x/9 -4/9=4
18x/45 - 10x/45 = 4+4/9
8x/45= 40/9
x= (40*45)/(9*8)
x= 25
x+2= 27
so the required numbers are 25, 27

Answer 2

let the two odd integers be x, x+2
2x/5 = 2(x+2)/9 + 4
2x/5 = 2x+4 / 9 + 36/9
[2x+4 + 36] / 9 - 2x/5 = 0
{[2x+40][5] - [2x*9]}/45 = 0
 10x + 200 - 18x / 45    = 0
  200 - 8x / 45 = 0
200 - 8x = 0*45
 200 - 8x = 0
8x = 200
 x  = 200/8
x   = 25



thuss, the digits are 25, 27
plz mark as brainliest