Math, asked by lekhya6515, 5 months ago

find two different solutions of 2x+3y=11​

Answers

Answered by Kitsch
2

Answer:

GIVEN = 2x + 3y = 11

TO FIND = TWO DIFFERENT SOLUTION

SOLUTION ( I ) IF X = 1

BY PUTTING IT IN EQUATION WE GET,

2 × 1 + 3y = 11

2 + 3y = 11

3y = 11 - 2

3y = 9

y = 9/3

y = 3

SOLUTION ( II ) IF X = 2

BY PUTTING IT IN EQUATION WE GET,

2 × 2 + 3y = 11

4 + 3y = 11

3y = 11 - 4

3y = 7

y = 7/3

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