Question

Find two digit multiple of a)2 or 3 b)2 and 3
steps also​

Answer 1

Answer:

We know, first two digit number divisible by 3 is 12 and last two digit number divisible by 3 is 99. Thus, we get

12,15,18,...,99 which is an AP

Here, a=12,d=3

Let there be n terms. Then,

an =99

a+(n−1)d=99

12+(n−1)3=99

n=29+1=30

Therefore, two digit numbers divisible by 3 are 30.

Answer 2

Answer:

6 because 2×3=6 3×2=6

Step-by-step explanation:

2×3=6

3×2=6