Question

Find two integer whose sum is 9 and difference is also 9​

Answer 1

Answer:

(-5) + (-4) =9 0-(-16) =16

Answer 2

Answer:

4and 5

Step-by-step explanation:

If the integers are a and b, then a+b=9=a^2-b^2.

b=9-a so we can substitute in a^2-b^2: a^2-(9-a)^2)=9.

(a-9+a)(a+9-a)=9.

(2a-9)9=9 so divide both sides by 9: 2a-9=1, 2a=10, a=5 and b=9-5=4.

So a+b=5+4=9, and 25-16=9. Both these check out OK, so 5 and 4 are the numbers.