find two integers whose sum is 2 and difference is 8?
Answers
Answered by
88
Let the two integers be x and y
A/Q,
x+y=2------(1)
x-y=8-------(2)
Solving (1) and (2) we get,
y= -3 and x= 5
A/Q,
x+y=2------(1)
x-y=8-------(2)
Solving (1) and (2) we get,
y= -3 and x= 5
Answered by
43
Answer:
Two integers are 5 and -3.
Solution:
Let us assume that the two integers are x and y,
As per the problem,
x+y=2
x=2-y -------- (a)
x-y=8 -------- (b)
Substituting a in b,
(2-y)-y=8
2-y-y=8
2-2y=8
-2y=8-2
-2y=6
-y=3
y=-3 -------- (c)
Substituting (c) in a
x=2-(-3)
x=2+3
x=5
Therefore, the two integers are 5 and -3.
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