Question

find two like fraction whose sum is 7/19 and difference is 2/19​

Answer 1

Step-by-step explanation:

Let the fractions be a/b and x/y

According to question

a/b + x/y = 7 / 11 ------(1)

a/b - x/y = 2 / 11 -------(2)

On adding equation 1 and 2, we get

2× a/b = ( 7 + 2) / 11

=> a/b = 9 / 22

Now,

On substituting the value of a/b in equation 1, we get

9 / 22 + x/y = 7 / 11

=> x/y = 7 / 11 - 9 / 22

=> x/y = ( 14 - 9) / 22

=> x/y = 5 / 22

First fraction = 9 / 22

Second fraction = 5 / 22

Answer 2

Answer:

Let the fractions be a/b and x/y

According to question

a/b + x/y = 7 / 19 ------(1)

a/b - x/y = 2 / 19 -------(2)

On adding equation 1 and 2, we get

2× a/b = ( 7 + 2) / 19

=> a/b = 9 / 38

Now,

On substituting the value of a/b in equation 1, we get

9 / 38 + x/y = 7 / 19

=> x/y = 7 / 19 - 9 / 38

=> x/y = ( 14 - 9) / 38

=> x/y = 5 / 38

First fraction = 9 / 38

Second fraction = 5 / 38