Math, asked by idoit, 1 year ago

Find two natural numbers, which differ by 3 & whose squares have the sum 149.

thedevnagpal: x-y=3
y=3+x

x²+y²=149
x²+(3+x)²=149
x²+9+x²+2(3x)= 149
2x²+9+6x=149
2x²+6x-140=0

taufik19: i have done the solution by other method

taufik19: my solution is correct and the anwer also

Answers

Answered by AmanKumarYadav123

14

Here is the solution

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Answered by taufik19

8

i hope it will help you

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