Question

Find two number such that one of then exceed the other by 6 and their sum is 18

Answer 1

let the first number be x

the second number exceed x by 6 so it is x+6

their sum is 18 so

x+(x+6)=18

x+x+6=18

2x+6=18

2x=18-6

2x=12

x=12/2

x=6

the first number =6

the second number=6+6=12