find two number whose sum is 27 and product is 182
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Answer:
Let the number be x, we get-
x(27-x) = 182
27x-x^2 = 182
x^2-27x+182 = 0
Now, use the method, splitting the middle term, we get-
x^2-27x+182
x^2-14x-13x+182
x(x-14)-13(x-14)
(x-14)(x-13)
Hence, required numbers are 13 or 14
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Solution:
Sol. Let one number be x, then other number be 27 - X
ATQ
⇒ x (27-x) = 182
⇒ x²- 27x + 182 = 0
⇒ x² -14x- 13x + 182 = 0
⇒ x (x - 14) - 13 (x - 14) = 0
⇒(x - 13) (x - 14) = 0
⇒ x - 13 = 0
or x- 14=10
⇒ x = 13
or x = 14
Hence, the numbers are 13 and 14.
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