Question

A metal alloy is made with 15% tin ,25% zinc and the rest with iron. How much iron would be needed to make 850 gram of alloy?

Answer 1

Answer:

since there is 15% tin 25% zinc

so there is 60% iron

now

60%of 850

=60/100×850

=6×85

=510 gram

510 gram iron is needed

Answer 2

Answer:510 grams

Step-by-step explanation:

% of iron in alloy = 100-(15+25)

=100-40

=60%

Amount of iron in alloy

=60*850/100

=6*85

=510gm