Question

find two number whose sum is 28 and seven times their difference is equal to four times of their sum

Answer 1

Hi ,

Let x and ( 28 - x ) are two numbers ,

7 times their difference = 4 times their

Sum

7 [ x - ( 28 - x ) ] = 4 × 28

x - 28 + x = 16

2x = 16 + 28

2x = 44

x = 44/2

x = 22

Therefore ,

Required two numbers are

x = 22 ,

28 - x = 28 - 22 = 6

( 22 , 6 )

I hope this helps you.

:)

Answer 2

x+y=28 ...(1)
7(x-y)=4(x+y)
7(x-y)=4*28
x-y=4*28/7
x-y=16...(2)
add both eq.(1)and(2):
x+y+x-y=28+16
2x=44
x=22
put x=22 in 1 we get:
y=6