Find two numbera which have hcf 6 and lcm 90
Answers
Answer:
Since HCF is 6, both the numbers should be multiples of 6, Condition(1). Let the numbers be n1 and n2. We know n1*n2=HCF*LCM=6*60=360. n2=360/n1.
2*3*3*5 is the prime factorization of 90.
2*45=90
5*18=90
6*15=90
9*10=90
Answer: (2and45), (5and18), (6and15), and (9and10)
Answer:
The two numbers are ( 6 , 90 ) ( 36 , 15 ).
Step-by-step explanation:
To find two numbers with HCF = 6 and LCM = 90.
There is a property of LCM and HCF where the product of HCF and LCM equals the product of two numbers. By factorizing both numbers we will find the numbers which share the same HCF and LCM.
LCM * HCF = x * y
By applying the above formula,
x * y = 90 * 6
= 540
By factorizing we get,
Factors of 540 = 2 * 2 * 3* 3 * 3 * 5
From this we get 2 sets of numbers which have the same HCF and LCM, They are ( 6 , 90 ) ( 36 , 15 )
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