find two numbers differing by 10 whose sum is equal to twice their difference?
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Let the 2 numbers be x and y.
According to question ,
x + 10 = y-----(I)
x + y = 20-----(II)
Putting value of y from I to II
x + x + 10 = 20
2x + 10 = 20
2x = 10
x = 5
Therefore the numbers are 5 and 15
According to question ,
x + 10 = y-----(I)
x + y = 20-----(II)
Putting value of y from I to II
x + x + 10 = 20
2x + 10 = 20
2x = 10
x = 5
Therefore the numbers are 5 and 15
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