Find two numbers in the ratio of 5 5\7 to 5 , such that when each is diminished by 12 1\2, they shall become in the ratio of 3 2\3 to 3.
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let ,
two no. is x:y in ratio 40/7:5
x:y = 40/7:5
x = 40/35y
x = 8/7 y
when each is diminished by 25/2 ,they shall become in the ratio 11/3 to 3
x-25/2:y-25/2= 11/3:3
2x-25/2:2y-25/2=11/3:3
3(2x-25/2)=11/3(2y-25/2)
6x-75 = 22y-275/3
18x-225=22y-275
18x-22y=-50
on putting the value of x in eqn
18(8/7y)-22y=-50
144y-154y=-350
-10y=-350
y=35
on putting the value of y in x
x= 8/7×35
x= 8×5
x= 40
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