Find two numbers such that one of the exceeds the other by 21 and their sum is 91.
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Answer:
Let the smaller number be x
The larger number will be x+9.
Given that their sum is 81.
Therefore, x+x+9=81
⇒2x+9=81
⇒2x=81−9
⇒2x=72
⇒x=36
Smaller number is 36.
Now, the larger number will be x+9=36+9=45.
Step-by-step explanation:
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